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Hi imagine I got this Latex expression from wikipedia: z_k = 2 \sqrt{\frac{-p}3} \cos{\left(\frac13\arccos{\left(\frac{-q}2\sqrt{\frac{27}{-p^3}}\right)}+ \frac{2k\pi}3\right)}\qquad\mbox{ avec }\qquad k\in{0,1,2}

is there a reverse function kind of retro-latex(z_k = 2 \sqrt{\frac{-p}3} \cos{\left(\frac13\arccos{\left(\frac{-q}2\sqrt{\frac{27}{-p^3}}\right)}+ \frac{2k\pi}3\right)}\qquad\mbox{ avec }\qquad k\in{0,1,2}) which will gives me the expression in classical form (not in Latex) ?

Hi imagine Imagine I got this Latex expression from wikipedia: wikipedia:

z_k = 2 \sqrt{\frac{-p}3} \cos{\left(\frac13\arccos{\left(\frac{-q}2\sqrt{\frac{27}{-p^3}}\right)}+ \frac{2k\pi}3\right)}\qquad\mbox{ avec }\qquad k\in{0,1,2}
k\in\{0,1,2\}

is there a reverse function kind of retro-latex(z_k $$ z_k = 2 \sqrt{\frac{-p}3} \cos{\left(\frac13\arccos{\left(\frac{-q}2\sqrt{\frac{27}{-p^3}}\right)}+ \frac{2k\pi}3\right)}\qquad\mbox{ avec }\qquad k\in{0,1,2}) k\in{0,1,2} $$

Is there a reverse function kind of

unlatex(z_k = 2 \sqrt{\frac{-p}3} \cos{\left(\frac13\arccos{\left(\frac{-q}2\sqrt{\frac{27}{-p^3}}\right)}+ \frac{2k\pi}3\right)}\qquad\mbox{ avec }\qquad k\in\{0,1,2\})

which will gives me the expression in classical form (not in Latex) ?Latex)?