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Why is Sage calling 1 a variable?

x = var('x') f = 1/(x-3)

limit(f,x=3,dir='below')

UnboundLocalError: local variable 'l' referenced before assignment

Why is Sage calling 1 a variable?

x = var('x') f = 1/(x-3)

limit(f,x=3,dir='below')

limit(f,x=3,dir='below')
  

UnboundLocalError: local variable 'l' referenced before assignment

assignment

Why is Sage calling 1 a variable?

x = var('x') f = 1/(x-3)

limit(f,x=3,dir='below')

UnboundLocalError: local variable 'l' referenced before assignment

Why is Sage calling 1 a variable?

x = var('x') f = 1/(x-3)

limit(f,x=3,dir='below')

UnboundLocalError: local variable 'l' referenced before assignment assignment

Why is Sage calling 1 a variable?

x = var('x') f = 1/(x-3)

limit(f,x=3,dir='below')

UnboundLocalError: local variable 'l' referenced before assignment

Why is Sage calling 1 a variable?

x = var('x') f = 1/(x-3)

limit(f,x=3,dir='below')

UnboundLocalError: local variable 'l' referenced before assignment

Why is Sage calling 1 a variable?

x = var('x') f = 1/(x-3)

limit(f,x=3,dir='below')

UnboundLocalError: local variable 'l' referenced before assignment

Why is Sage calling 1 a variable?

x = var('x') f = 1/(x-3)

limit(f,x=3,dir='below')

UnboundLocalError: local variable 'l' referenced before assignment

Why is Sage calling 1 a variable?

x = var('x') f = 1/(x-3) Consider

x = var('x') 
f = 1/(x-3) 

limit(f,x=3,dir='below')

UnboundLocalError: local variable 'l' referenced before assignment

Why is Sage calling 1 a variable?

Consider

x = var('x') 
f = 1/(x-3) 

limit(f,x=3,dir='below')

UnboundLocalError: local variable 'l' referenced before assignment