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Hello

I'm looking for solution when bigger number of variables is in the picture.

Simple example: There is relationship I = V/R then we know that R = 3, with that knowledge let's plot I(V) in sage it should look something like: V = var('V') R = var('R') I = V/R R = 3 plot(I)

but above is not working, because in plot(I) I is still V/R not V/3 (knowledge of R=3 is not used), so I'm looking for some operation that turns V/R into V/3, something like I = evaluate(I) but such evaluate() apparently does not exist

there are however two different ways (1) repeat I=V/R after R=3 and in such situation I becomes V/3 as needed (2) I = I(R=R) and with earlier R=3, I also becomes V/3 both however seems for me be solution(s) for simple expression with just few varables, and not good (not as straightforward as hypothetical I = evaluate(I) ) for more complex expression with several varables.

Is such evaluate() or so, available already, and I failed to find it? Is there a (easy) way to implement that proposed evaluate() ?

Hello

I'm looking for solution when bigger number of variables is in the picture.

Simple example: There is relationship I = V/R then we know that R = 3, with that knowledge let's plot I(V) in sage it should look something like: like:

V = var('V')
R = var('R')
I = V/R
R = 3
plot(I)
plot(I)

but above is not working, because in plot(I) I is still V/R not V/3 (knowledge of R=3 is not used), so I'm looking for some operation that turns V/R into V/3, something like like

I = evaluate(I)

but such evaluate() apparently does not exist

there are however two different ways ways
(1) repeat I=V/R after R=3 and in such situation I becomes V/3 as needed needed
(2) I = I(R=R) and with earlier R=3, I also becomes V/3 both however seems for me be solution(s) for simple expression with just few varables, variables, and not good (not as straightforward as hypothetical I = evaluate(I) ) for more complex expression with several varables.variables.

Is such evaluate() or so, available already, and I failed to find it? it?
Is there a (easy) way to implement that proposed evaluate() ?

Hello

I'm looking for solution when bigger number of variables is in the picture.

Simple example: There is relationship I = V/R then we know that R = 3, with that knowledge let's plot I(V) in sage it should look something like:

V = var('V')
R = var('R')
I = V/R
R = 3
plot(I)

but above is not working, because in plot(I) I is still V/R not V/3 (knowledge of R=3 is not used), so I'm looking for some operation that turns V/R into V/3, something like

I = evaluate(I)

but such evaluate() apparently does not exist

there are however two different ways
(1) repeat I=V/R after R=3 and in such situation I becomes V/3 as needed
(2) I = I(R=R) and with earlier R=3, I also becomes V/3
both however seems for me be solution(s) for simple expression with just few variables, and not good (not as straightforward as hypothetical I = evaluate(I) ) for more complex expression with several variables.

Is such evaluate() or so, available already, and I failed to find it?
Is there a (easy) way to implement that proposed evaluate() ?

Hello

I'm looking for solution when bigger number of variables is in the picture.

Simple example: There is relationship I = V/R then we know that R = 3, with that knowledge let's plot I(V) in sage it should look something like:

V = var('V')
R = var('R')
I = V/R
R = 3
plot(I)

but above is not working, because in plot(I) I is still V/R not V/3 (knowledge of R=3 is not used), so I'm looking for some operation that turns V/R into V/3, something like

I = evaluate(I)

but such evaluate() apparently does not exist

there are however two different ways
(1) repeat I=V/R after R=3 and in such situation I becomes V/3 as needed
(2) I = I(R=R) and with earlier R=3, I also becomes V/3
both however seems for me be solution(s) for simple expression with just few variables, and not good (not as straightforward as hypothetical I = evaluate(I) ) for more complex expression with several variables.

Is such evaluate() or so, available already, and I failed to find it?
Is there a (easy) way to implement that proposed evaluate() ?

Hello

I'm looking for solution when bigger number of variables is in the picture.

Simple example: There is relationship I = V/R then we know that R = 3, with that knowledge let's plot I(V)
in sage it should look something like:

V = var('V')
R = var('R')
I = V/R
R = 3
plot(I)

but above is not working, because in plot(I) I is still V/R not V/3 (knowledge of R=3 is not used), so I'm looking for some operation that turns V/R into V/3, something like

I = evaluate(I)

but such evaluate() apparently does not exist

there are however two different ways
(1) repeat I=V/R after R=3 and in such situation I becomes V/3 as needed
(2) I = I(R=R) and with earlier R=3, I also becomes V/3
both however seems for me be solution(s) for simple expression with just few variables, and not good (not as straightforward as hypothetical I = evaluate(I) for more complex expression with several variables.

Is such evaluate() or so, available already, and I failed to find it?
Is there a (easy) way to implement that proposed evaluate() ?

Hello

I'm looking for solution when bigger number of variables is in the picture.

Simple example: There is relationship I = V/R then we know that R = 3, with that knowledge let's plot I(V)
in sage it should look something like:

V = var('V')
R = var('R')
I = V/R
R = 3
plot(I)

but above is not working, because in plot(I) I is still V/R not V/3 (knowledge of R=3 is not used), so I'm looking for some operation that turns V/R into V/3, something like

I = evaluate(I)

but such evaluate() apparently does not exist

there are however two different ways
(1) repeat I=V/R after R=3 and in such situation I becomes V/3 as needed
(2) I = I(R=R) and with earlier R=3, I also becomes V/3
both however seems for me be solution(s) for simple expression with just few variables, and not good (not as straightforward as hypothetical I = evaluate(I) for more complex expression with several variables.

Is such evaluate() or so, available already, and I failed to find it?
Is there a (easy) way to implement that proposed evaluate() ?