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LU descomposition for a matrix

There is an inconsistency in the use of the LU decomposition of a matrix. If matrix A is declared in the RDF ring then P, L, U = A.LU () provides PA = LU but if A is declared in the RR ring (or QQ, ZZ,...) then A = PLU. Therefore in a case P is P.transpose () on the other.

 2 retagged tmonteil 25173 ●29 ●178 ●468 http://wiki.sagemath.o...

LU descomposition for a matrix

There is an inconsistency in the use of the LU decomposition of a matrix. If matrix A is declared in the RDF ring then P, L, U = A.LU () provides PA = LU but if A is declared in the RR ring (or QQ, ZZ,...) then A = PLU. Therefore in a case P is P.transpose () on the other.

 3 No.3 Revision calc314 4151 ●21 ●48 ●111

LU descomposition decomposition for a matrix

There is an inconsistency in the use of the LU decomposition of a matrix. If matrix A is declared in the RDF ring then P, L, U = A.LU () provides PA = LU but if A is declared in the RR ring (or QQ, ZZ,...) then A = PLU. Therefore in a case P is P.transpose () on the other.

 4 retagged FrédéricC 4314 ●3 ●37 ●90

LU decomposition for a matrix

There is an inconsistency in the use of the LU decomposition of a matrix. If matrix A is declared in the RDF ring then P, L, U = A.LU () provides PA = LU but if A is declared in the RR ring (or QQ, ZZ,...) then A = PLU. Therefore in a case P is P.transpose () on the other.