There is an inconsistency in the use of the LU decomposition of a matrix. If matrix A is declared in the RDF ring then P, L, U = A.LU () provides PA = LU but if A is declared in the RR ring (or QQ, ZZ,...) then A = PLU. Therefore in a case P is P.transpose () on the other.
Revision history [back]
 | 1 | initial version |
LU descomposition for a matrix
| | 2 | retagged |
LU descomposition for a matrix
There is an inconsistency in the use of the LU decomposition of a matrix. If matrix A is declared in the RDF ring then P, L, U = A.LU () provides PA = LU but if A is declared in the RR ring (or QQ, ZZ,...) then A = PLU. Therefore in a case P is P.transpose () on the other.
| | 3 | No.3 Revision |
LU descomposition decomposition for a matrix
There is an inconsistency in the use of the LU decomposition of a matrix. If matrix A is declared in the RDF ring then P, L, U = A.LU () provides PA = LU but if A is declared in the RR ring (or QQ, ZZ,...) then A = PLU. Therefore in a case P is P.transpose () on the other.
| | 4 | retagged |
LU decomposition for a matrix
There is an inconsistency in the use of the LU decomposition of a matrix. If matrix A is declared in the RDF ring then P, L, U = A.LU () provides PA = LU but if A is declared in the RR ring (or QQ, ZZ,...) then A = PLU. Therefore in a case P is P.transpose () on the other.
| | 5 | retagged |
LU decomposition for a matrix
There is an inconsistency in the use of the LU decomposition of a matrix. If matrix A is declared in the RDF ring then P, L, U = A.LU () provides PA = LU but if A is declared in the RR ring (or QQ, ZZ,...) then A = PLU. Therefore in a case P is P.transpose () on the other.
