Hello
I am newbie to sagemath. I have windows 8 and sage version is 6.4.1. I am running it inside virtualbox. I was reading some thing about solving equations on sage website at http://www.sagemath.org/doc/reference/calculus/sage/symbolic/relation.html
At one point author is trying to demonstrate the use of optional keywords for the "solve" He is solving equation
solve(abs(1-abs(1-x)) == 10, x)
When evaluated this gives
[abs(abs(x - 1) - 1) == 10]
But when the input is modified a little as
solve(abs(1-abs(1-x)) == 10, x, to_poly_solve=True)
sage gives correct result as [x == -10, x == 12]
So why does it not work in the first case ? I didn't understand this use of keyword to_poly_solve.
I tried to post this question on sage-support but for some reason my posted question doesn't seem to appear there.
Please help sundar
