Here are two approaches.
Building each row as a list...
b=0
c=[]
for i in [1..10]:
tmp=[]
for j in [1..10]:
b+=1
tmp.append(b)
c.append(tmp)
d=matrix(c)
print d
d[0,1]
Using nested list comprehensions...
c=[[10*j+i for i in [1..10]] for j in [0..9]]
d=matrix(c)
d
I don't know here whether you would prefer a list or a matrix or an array as your final data type. But, here is one solution that first builds a list, in case you'd rather have a list. I'm sure there are many other more efficient solutions depending on what you want in the larger picture of what you are doing.
a=0
b=[]
for i in [1..10]:
a+=1
b.append(a)
matrix(b)
Thanks for the answer. Suppose I want to create a 2D matrix and I have to access its rows or columns or an individual elements. My data type caan be int/float/real number. What can be a solution in this case. An equivalent MATLAB code can be like this.
a = 0
b = 0
c = 0
for i = 1:10
for j = 1:10
b = b +1
c(i,j) = b
end
end
d = c(1,2)
Sorry I am quite new user of sage.
Asked: 2013-02-22 08:13:52 +0200
Seen: 535 times
Last updated: Feb 25 '13
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