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Symbolic to numerical array

asked 2017-09-13 09:56:12 -0500

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I would like to get a number-valued array from a symbolic-valued array, for example:

( sin(1), cos(1), pi/4) to ( sin(1).n() , cos(1).n() , pi/4.n() )

WITHOUT having to convert one component at a time, but directly transforming the array. When I write

( sin(1), cos(1), pi/4 ).n()

I get 'Error'. I would greatly appreciate any help :)

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answered 2017-09-14 12:00:41 -0500

dan_fulea gravatar image

The answer of fidbc using list comprehension is all needed. This is a python native solution.

But just to see how versatile sage is, we can use a tacit conversion of the given tuple to a vector over a declared field. (We use the constructor for this class, which is vector.) The field may be RR, reals with default precision, or RealField(100) if we want to set our precision. For the purist, if we really need a tuple back, there is also a conversion back to tuple...

So the one-liner would be tuple( vector( RR, ( sin(1), cos(1), pi/4 ) ) ) . (With or without the conversion to tuple.

Sample code following the same idea:

sage: t = ( sin(1), cos(1), pi/4 ) 
sage: vector( RR, t )
(0.841470984807897, 0.540302305868140, 0.785398163397448)
sage: type( _ )
<type 'sage.modules.free_module_element.FreeModuleElement_generic_dense'>
sage: tuple( vector( RR, t ) )
(0.841470984807897, 0.540302305868140, 0.785398163397448)
sage: type( _ )
<type 'tuple'>
sage: IR = RealField( 100 )
sage: tuple( vector( IR, t ) )
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answered 2017-09-13 10:15:33 -0500

fidbc gravatar image

updated 2017-09-13 10:16:00 -0500


[n(x) for x in ( sin(1), cos(1), pi/4 )]

count as a single command? If L is the list of numbers, say L=( sin(1), cos(1), pi/4), then map(n,L) should do the job.

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Asked: 2017-09-13 09:56:12 -0500

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Last updated: Sep 14