It seems to work fine for me:
sage: var('x')
x
sage: f=function('f',nargs=1)
sage: f
f
sage: f == f
True
sage: f(x) == f(x)
f(x) == f(x)
sage: bool(f(x) == f(x))
True
sage: if f(x) == f(x):
....: print 'equal!'
....:
equal!
Do you mean that you want f(x) == f(x) to be automatically simplified to True, instead of returning an equation? That can't work in general, because in Sage, an equation is False if Sage can't prove that it's true. So if you had an equation like
sage: x^2 - 4 == 0
x^2 - 4 == 0
it would instead give you False rather than the equation, because it's possible that x is something other than 2 or -2..
Long story short, if you want the truth value, call bool. You might be able to construct a subclass which gives you the behaviour you want but ISTM it'll only lead to headaches.
Yes, I was expecting f(x)==f(x) to automatically simplify to True. (Mathematica will actually do so.) The bool()-typing workaround you suggest is kind of ok for me, yet, as I read your answer, it seems really strange that x-x==0 does not result in True but rather in 0==0 ... and moreover, if you type 0==0 at the sage prompt you will obviously get True ...
Asked: 2012-12-01 13:04:56 +0100
Seen: 589 times
Last updated: Dec 01 '12
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