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Forcing Prime Notation

asked 2012-11-26 00:19:07 +0200

hwong557 gravatar image

I want sage to implicitly differentiate a function for me, say

d/dx f(x)^2 = 2f(x)* f'(x).

I can do this by entering:

f=function('f', x)

This returns

2 f(x) D[0] (f) (x)

which is correct, but hard for me to read. Can I make sage return:

2 f(x) f'(x)


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answered 2012-11-26 07:09:20 +0200

You can try the patch attached to issue #6344. It is more than 3 years old, so some work might be needed to make it apply to a recent Sage version, but it essentially does exactly what you need. See this comment for some examples.

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"However, I think we should settle on an output style ASAP, without letting too many releases go by." Oops. Perhaps this is still worth changing? Would we need deprecation?

kcrisman gravatar imagekcrisman ( 2012-11-26 10:30:06 +0200 )edit

answered 2012-11-26 03:18:01 +0200

achrzesz gravatar image

updated 2012-11-26 10:30:44 +0200

kcrisman gravatar image

This is easy to read:

sage: maxima('diff(f(x)^2,x)')                 


sage: from sympy import *                      
sage: x=Symbol('x')      
sage: f=Function('f')    
sage: diff(f(x)^2,x)     
2*f(x)*Derivative(f(x), x)


sage: maxima_console()
(%i1) derivabbrev:true;
(%o1)                                true
(%i2) diff(f(x)^2,x);
(%o2)                            2 f(x) f(x)
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Asked: 2012-11-26 00:19:07 +0200

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Last updated: Nov 26 '12