Interpreting ints as ints

int
integer

asked 2012-01-23 13:01:00 +0100

kartikv
31 ●1 ●1 ●4

I am working with a python package called Theano, which has a function called "function" which basically takes in the symbolic representation of a function and compiles it for fast execution on a block of memory either on a CPU or a GPU. When trying to use it in sage, however, it gets a bit flummoxed by the fact that integers and such are interpreted as sage integers, rather than python basic types. Is there a way to (at runtime) turn off that part of the interpreter, so that code doesn't have to be rewritten to work in sage?

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answered 2012-01-23 13:26:44 +0100

Jason Grout
3505 ●9 ●36 ●81

updated 2012-01-23 13:27:49 +0100

You can turn off the preparser altogether:

sage: type(1)
<type 'sage.rings.integer.Integer'>
sage: preparser(False)
sage: type(1)
<type 'int'>

If you are running sage on a .py file, it should not preparse the file. If it is a .sage file, then preparsing happens by default (but you can turn it off like above, I think).

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Asked: 2012-01-23 13:01:00 +0100

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Last updated: Jan 23 '12

Interpreting ints as ints edit

1 Answer