Interpreting ints as ints

int
integer

asked 2012-01-23 13:01:00 +0100

kartikv
31 ●1 ●1 ●4

I am working with a python package called Theano, which has a function called "function" which basically takes in the symbolic representation of a function and compiles it for fast execution on a block of memory either on a CPU or a GPU. When trying to use it in sage, however, it gets a bit flummoxed by the fact that integers and such are interpreted as sage integers, rather than python basic types. Is there a way to (at runtime) turn off that part of the interpreter, so that code doesn't have to be rewritten to work in sage?

edit retag flag offensive close merge delete

add a comment

1 Answer

Sort by » oldest newest most voted

answered 2012-01-23 13:26:44 +0100

Jason Grout
3505 ●9 ●36 ●81

updated 2012-01-23 13:27:49 +0100

You can turn off the preparser altogether:

sage: type(1)
<type 'sage.rings.integer.Integer'>
sage: preparser(False)
sage: type(1)
<type 'int'>

If you are running sage on a .py file, it should not preparse the file. If it is a .sage file, then preparsing happens by default (but you can turn it off like above, I think).

edit flag offensive delete link

add a comment

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

Stats

Asked: 2012-01-23 13:01:00 +0100

Seen: 285 times

Last updated: Jan 23 '12

Interpreting ints as ints edit

1 Answer