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extracting the coefficients of a linear combination

asked 2011-08-28 10:23:10 +0200

Menny gravatar image

Let me just say that I'm quite new to sage (although I'm making a progress!)

I wish to input a number field (in my case real quadratic field), a basis $w_1,w_2$ over $ \mathbb Q$ and an element $v$ of this number field and get the coefficient of $v$ as a linear combination of $w_1$ and $w_2$. I.e., if $v=aw_1+bw_2$ I wish to get (a,b).

I tried doing this with just solving equations in matrices but I didn't find a way to make it solve the equations over the base field $ \mathbb Q$.

Thanks a lot for helping! Menny

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answered 2011-08-31 10:23:17 +0200

Volker Braun gravatar image

I take it you understand how to get the coefficients in the standard basis, e.g.:

sage: var('x')
sage: K.<a> = NumberField(x^2+1)
sage: 3+5*a+a^2                 
5*a + 2
sage: (3+5*a+a^2).vector()
(2, 5)

Then going to your preferred basis is just a linear algebra problem. For example, if your preferred QQ-basis is (1,1) and (2,0) then you could do:

sage: Q2 = (QQ^2).span_of_basis([(1,1), (2,0)]);  Q2
Vector space of degree 2 and dimension 2 over Rational Field
User basis matrix:
[1 1]
[2 0]
sage: Q2.coordinates([2,5])                         
[5, -3/2]

Check that this is correct:

sage: 5*vector([1,1]) + (-3/2)*vector([2,0])        
(2, 5)
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thanks a lot! this is an act of pure giving... Menny

Menny gravatar imageMenny ( 2011-08-31 11:24:49 +0200 )edit

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Asked: 2011-08-28 10:23:10 +0200

Seen: 2,112 times

Last updated: Aug 31 '11