any way to turn off error msg when I catch the errors?

asked 2011-02-11 13:19:00 +0100

Shu
173 ●9 ●14 ●21

updated 2023-01-10 00:01:09 +0100

tmonteil
27413 ●31 ●204 ●517 http://wiki.sagemath.o...

trying to check whether a numerical expression is NaN or not. My expression is log(arcsin(e)). If I apply N() on the expression it goes into infinite loop. I try to catch the runtime error. Everything seems to work in the following code except the error message displayed. I do not want that message in output. Any way to turn the error message off.

sage: def number(expr):
....:         try:
....:             n = N(expr)
....:     except (RuntimeError):
....:             n = N(NaN)
....:     return n
....: 
sage: expr=log(arcsin(e))
sage: a=number(expr)
Exception RuntimeError: 'maximum recursion depth exceeded in __subclasscheck__' in <type 'exceptions.RuntimeError'> ignored
# I do not want the above error message in output
sage: a
NaN
sage: a.is_NaN()
True

answered 2011-02-11 13:40:40 +0100

niles
4529 ●23 ●72 ●133 http://nilesjohnson.net/

updated 2011-02-12 08:27:50 +0100

This certainly is weird. I think you have an indentation problem in your post, but that doesn't seem to be the problem.

The following is slightly simpler, but also prints the error message for me. (It also prints the error message when I use except RuntimeError)

def number(expr):
    try:    
        n = N(expr)
    except:
        n = 0
    return n

Note, by contrast, that the following works without problem (no error message printed):

def divide(n):
    try:
        r = 1/n
    except ZeroDivisionError:
        r = Infinity
    return r

So it seems this is a bug with the recursion depth RuntimeError . . .

UPDATE: Based on the discussion, I've filed a ticked for this: #10774

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Comments

Yes, I think it's a bug in Sage: running `N(log(arcsin(e)))`, or just `N(log(NaN))`, seems to send Sage into an infinite loop, hence the error. Can you catch an error produced by an infinite loop?

John Palmieri ( 2011-02-11 15:34:31 +0100 )edit

Amusingly, complex(log(arcsin(e))) gives 0.82572700817589695+0.81223539737883776j, which works. And you can catch at least some recursion RuntimeErrors; def f(x): f(x) can be caught that way.

DSM ( 2011-02-11 15:55:45 +0100 )edit

You know, I don't think this _is_ an Exception. I think the reason we can't catch it is because it's been swallowed, and the above is just a print statement. So we'd need to find where it's being printed, and then maybe we could monkeypatch it.

DSM ( 2011-02-11 16:20:02 +0100 )edit

In any case, I think we're agreed that it's a bug, and a ticket should be filed, right?

niles ( 2011-02-11 16:57:19 +0100 )edit

Yeah, I think both you and John are right, this is a bug.

DSM ( 2011-02-11 23:49:49 +0100 )edit

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