Using matrix elements as arguments

I have a rather easy question, or so it would seem. I have looked for an answer but was unable to find one anywhere so I'm asking it here.

I am making a very simple iterative algorithm for which the input as well as the output at the end of every iteration is a vector (or matrix for that matter). What I want to do is use these elements as arguments for several functions during each of the iteration. So for example

x=var('x')
y=var('y')
z=matrix(2,1,[ [1],[1] ]
f=x^2+y^3
H=f.hessian()


Then what I would like to do is say

H(z[0],z[1])


or

H(z)


But no matter what I try I can't seem to get it to work. Ideas?

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There is a subtle difference between "symbolic expressions" and "callable symbolic expressions", which are also termed "functions". Writing

sage: f=x^2+y^3


makes f a symbolic expression, which displays as

sage: f
x^2 + y^3


On the other hand, writing

sage: g(x,y)=x^2+y^3


makes g a callable symbolic expression, which displays as

sage: g
(x, y) |--> x^2 + y^3


With f, you need to use f.substitute to substitute values, but with g, since you have already informed sage of the variable order, you can use it like a function

sage: g(1,3)
28


The way you define your finction determines what kind of expression the corresponding Hessian is; note the difference in syntax below:

First method:

sage: x=var('x')
sage: y=var('y')
sage: z=matrix(2,1,[ [1],[1] ])
sage: f=x^2+y^3
sage: H=f.hessian()
sage: H.substitute(x=z[0,0],y=z[1,0])
[2 0]
[0 6]

sage: f
x^2 + y^3
sage: H
[  2   0]
[  0 6*y]


Second method, making g a callable symbolic expression:

sage: x=var('x')
sage: y=var('y')
sage: z=matrix(2,1,[ [1],[1] ])
sage: g(x,y)=x^2+y^3
sage: H=g.hessian()
sage: H(z[0,0],z[1,0])
[2 0]
[0 6]

sage: g
(x, y) |--> x^2 + y^3
sage: H
[  (x, y) |--> 2   (x, y) |--> 0]
[  (x, y) |--> 0 (x, y) |--> 6*y]

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This works for me:

sage: H.substitute(x=z[0,0],y=z[1,0])


(z is a matrix, so it requires two indices to specify an element.)

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I guess

H = f.hessian().function(x,y)
H(z[0,0],z[1,0])


would also work

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Last updated: Jan 05 '15