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Bold in table

asked 2022-11-18 14:47:52 +0200

Cyrille gravatar image

updated 2022-11-20 18:27:30 +0200

For the following code

list_collab = ["A_0", "I_0", "E_0", "A_1", "I_1", "E_1"]
collab = set(list_collab)
subcollab = Subsets(collab,3,submultiset=True)
affinites= [[ZZ.random_element(1,5) for i in range(0,5)] for j in range(0,4)]
list_collab1 = ['']+list_collab[0:]
list_collab2 = [r'<b style="color:black">$'+x+r'$</b>' for x in list_collab1]
table_aff =table(affinites, header_row=list_collab, header_column=list_collab2)

No strong problem with the table if I can have indexed values in header rows.

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And your question is ?

Emmanuel Charpentier gravatar imageEmmanuel Charpentier ( 2022-11-18 18:20:43 +0200 )edit

Yes a question would be nice, but if you run this little program you will see there is a un the first cell.

Cyrille gravatar imageCyrille ( 2022-11-19 15:32:29 +0200 )edit

First, it would help if you provided a minimal example that demonstrated the problem. For example, remove all lines involving the variable collab from this altogether.

John Palmieri gravatar imageJohn Palmieri ( 2022-11-19 19:30:38 +0200 )edit

Second, it looks a lot better if I change list_collab2 to ... for x in list_collab rather than for x in list_collab1: list_collab1 has an empty first entry.

John Palmieri gravatar imageJohn Palmieri ( 2022-11-19 19:31:45 +0200 )edit

Finally, is the * at the end intentional?

John Palmieri gravatar imageJohn Palmieri ( 2022-11-19 19:32:19 +0200 )edit

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answered 2022-11-22 20:34:39 +0200

With your code, I get this output: image description

If I make two changes — namely, changing the definition of affinites to use for i in range(0,6) and changing the definition of list_collab2 to use for x in list_collab — then I get this: image description

It is not clear what you are hoping to get, but the second version certainly looks better than the first one.

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Asked: 2022-11-18 14:47:52 +0200

Seen: 161 times

Last updated: Nov 22 '22