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How to define Z(1/sqrt(2),I)

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• abelian_group
• ring

asked 2022-10-27 11:36:52 +0100

pierrick Bournez
11 ●1

Hello, I'm kinda new to sage maths and I would like to define the ring generated by 1/sqrt(2) and i . I've been looking on internet and I found nothing.

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Is this what you want?

R.<x> = PolynomialRing(ZZ[I])
K.<y> = NumberField(2*x^2 - 1)

Max Alekseyev ( 2022-10-31 20:53:49 +0100 )edit

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