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Construct local ring of function field variety

asked 2 years ago

narodnik gravatar image

Hello sage community,

I want to localize a variety's field at a certain point. First I construct the field of fractions K(V) for a coordinate ring K[V]

K.<x, y> = GF(11)[]
S = K.quotient(y^2 - x^3 - 4*x).fraction_field()

Now I wish to construct the ideal x2, but unforunately 1/(x2)S so I=S.

sage: I = S.ideal(x - 2)
sage: I
Principal ideal (1) of Fraction Field of Quotient of Multivariate Polynomial Ring in x, y over Finite Field of size 11 by the ideal (-x^3 + y^2 - 4*x)

How can I exclude all denominators from the fraction field corresponding to x=2,y=4?

That is S is all f/gK[V]:g(2,4)0.

Thank you

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I do not understand what it means to exclude denominators. Even if g1(2,4)0 and g2(2,4)0, we still may have g1(2,4)+g2(2,4)=0. That is, such polynomials do not form an ideal.

Max Alekseyev gravatar imageMax Alekseyev ( 2 years ago )

Maybe I should have excluded the part about the ideal. I just want to construct the local ring, which is K[V]P aka the coordinate ring localized at a certain point. This means excluding all denominators which are a zero at P.

narodnik gravatar imagenarodnik ( 2 years ago )

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answered 2 years ago

narodnik gravatar image
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Asked: 2 years ago

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Last updated: Aug 01 '22