Looping with function having an object as a parameter

asked 2022-05-13 20:16:10 +0100

vidyarthi gravatar image

Consider the following code:

def Sier(H):
      for i in list(range(1,H.order())):
           H.disjoint_union(H)
      return H
f=Sier(graphs.CompleteGraph(5))
f.order()

I get the output as 5. But, what I actually wanted was:

def Sier(n,k):
    l=list(range(1,k))
    g=graphs.CompleteGraph(n)
    for i in l:
        g=g.disjoint_union(graphs.CompleteGraph(n))
    return g
 k=Sier(5,5)
 k.order()

which gives me the correct output as 25. I ask as to what is the problem with the first code, like how to get $k$ disjoint copies of a graph $H$ with order $k$?

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Comments

You do not make any assignment in the first code and your graph H remains unchanged.

Max Alekseyev gravatar imageMax Alekseyev ( 2022-05-13 23:45:31 +0100 )edit