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Looping in graphs

asked 2022-05-13 08:42:20 +0200

vidyarthi gravatar image

When I run the code:

l=[1,2,3,4,5]
s=graphs.CompleteGraph(1)
for i in l:
    t=s.disjoint_union(graphs.CompleteGraph(i+1))
t.order()

I get the output as $7$, which not as the expected $21$. How do I rectify this? How to loop over graphs? Any hints? Thanks beforehand.

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Comments

It's hard to answer without the exact question. Currently your code is equivalent to

t = graphs.CompleteGraph(1).disjoint_union(graphs.CompleteGraph(6))

Indeed, you always take the disjoint union with s without modifying s.

David Coudert gravatar imageDavid Coudert ( 2022-05-13 08:58:52 +0200 )edit

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answered 2022-05-13 09:53:49 +0200

tmonteil gravatar image

updated 2022-05-13 09:54:05 +0200

In your code, at each loop, the graph t is reconstructed from the initial s, which is never modified. If you want to accumulate your changes, you need to modify s:

l=[1,2,3,4,5]
s=graphs.CompleteGraph(1)
for i in l:
    s=s.disjoint_union(graphs.CompleteGraph(i+1))
s.order()

By the way, you can replace l with range(1,6)

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Asked: 2022-05-13 08:42:20 +0200

Seen: 19 times

Last updated: May 13