Is there a way to define infinitely many variables? At the moment, I am able to define arbitrarily big number of symbolic variables, x[i], using a code as follows:
N=3
x=np.zeros(shape=(N),dtype=object)
for i in range(N):
x[i]=var('x_', n=N )[i]
I would like to be able to define x_i for i=1,2,... Is this possible using the symbolic ring?
You can not create infinitely many symbols (a.k.a. symbolic variables) in the sense that they will fill up your memory, but you can create as many such symbols on demand (lazily). As a quick example, you can define the following function:
sage: def x(i):
....: return SR.var('x_{}'.format(i))
Then, you can do things like:
sage: x(4)
x_4
sage: x(4) + x(7)^2
x_7^2 + x_4
sage: sum(x(i)^i for i in range(10))
x_9^9 + x_8^8 + x_7^7 + x_6^6 + x_5^5 + x_4^4 + x_3^3 + x_2^2 + x_1 + 1
Note that if you reuse twice the same symbol, it is not recreated:
sage: x(2) is x(2)
True
In case you prefer indexing syntax x[i] over function call syntax x(i), you can use the following helper class:
from collections import defaultdict
class keydefaultdict(defaultdict):
def __missing__(self, key):
if self.default_factory is not None:
ret = self[key] = self.default_factory(key)
return ret
else:
raise KeyError(key)
Then:
sage: x = keydefaultdict(lambda i: SR.var('x_{}'.format(i)))
sage: x[1]
x_1
sage: x[12]
x_12
Asked: 2022-02-02 21:41:45 +0100
Seen: 312 times
Last updated: Feb 03 '22
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