# How to reduce a list of fractions

I have a list of integers. I want to divide (n+1) by n. I can do this with no problem, but I can't get the resulting fractions in reduced form. My list has 50 items, but I'll only do a list of 5 here to avoid spamming.

```
sage: a = [6198089008491993412800, 3099044504245996706400, 2066029669497331137600, 2324283378184497529800, 1239617801698398682560]
sage: c = [(n + 1)/n for n in a]
sage: print (c)
[6198089008491993412801/6198089008491993412800, 3099044504245996706401/3099044504245996706400, 2066029669497331137601/2066029669497331137600, 2324283378184497529801/2324283378184497529800, 1239617801698398682561/1239617801698398682560]
```

I don't know why Sage doesn't automatically reduce these fractions, but since it doesn't, I've tried multiplying by 1 and using reduce() and simplify(), and have searched everywhere I could think of for an answer, but nothing works. I apologize in advance for asking such a rudimentary question.

n+1 is coprime with n => these fractions are reduced

Thank you! I didn't pay attention to the output of Sage. I'm trying to divide each term in the list by the term before it, but that's not what I asked for in Sage. Alas, I can't figure out how to ask for what I want. I tried using a(n) and a(n+1) and also creating the list L, but I couldn't get either of those to produce what I'm looking for.

(The result I am looking for is [1/2, 2/3, 9/8, 8/15]. )

This is a python question. Learn python first ?

`a[0]`

will give 6198089008491993412801/6198089008491993412800, for example.`for n in range(len(a)-1): ...`

Thank you, FrédéricC. I went to Python, which I have been studying, slowly, and (of course) with some help from the Stack Overflow forum, figured out to do this in Python.