Get denominator with hold=True

denominator

asked 2021-04-25 22:05:18 +0100

Anonymous

updated 2023-05-19 18:44:18 +0100

slelievre
17684 ●22 ●160 ●349 http://carva.org/samue...

I am struggling to get the denominator of an expression defined with hold=True.

The expression is a quotient with a common factor in the numerator and denominator.

I don't want the common factor to be cleared out.

Example:

sage: t2 = x.mul(1 / (x^2 - x), hold=True)

sage: t2
x/(x^2 - x)

sage: t2.denominator()
x - 1

This results in x - 1 instead of x*(x - 1) or x^2 - x.

Is there any other way to obtain x^2 - x?

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answered 2021-04-25 23:37:37 +0100

vdelecroix
7645 ●20 ●85 ●168 http://www.labri.fr/pe...

updated 2021-04-25 23:38:44 +0100

To find out about the possible extra arguments of a method you could access its documentation with a question mark. Here

sage: t2.denominator?
Docstring:     
   Return the denominator of this symbolic expression

   INPUT:

   * "normalize" -- (default: "True") a boolean.

   If "normalize" is "True", the expression is first normalized to
   have it as a fraction before getting the denominator.

   If "normalize" is "False", the expression is kept and if it is not
   a quotient, then this will just return 1.

Hence in your situation you could do

sage: t2.denominator(normalize=False)                                                                                                                                                          
x^2 - x

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Thx. 🙈🙈🙈

Damm ( 2021-04-26 08:37:24 +0100 )edit

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Asked: 2021-04-25 22:03:53 +0100

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Last updated: May 19 '23

Get denominator with hold=True edit