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Get denominator with hold=True

asked 2021-04-25 22:05:18 +0100

anonymous user

Anonymous

t2=x.mul(1/(x^2-x),hold=True) t2.denominator()

results in x-1 instead of x*(x-1) or x^2-x. Is there any other way to obtain x^2-x?

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answered 2021-04-25 23:37:37 +0100

vdelecroix gravatar image

updated 2021-04-25 23:38:44 +0100

To find out about the possible extra arguments of a method you could access its documentation with a question mark. Here

sage: t2.denominator?
Docstring:     
   Return the denominator of this symbolic expression

   INPUT:

   * "normalize" -- (default: "True") a boolean.

   If "normalize" is "True", the expression is first normalized to
   have it as a fraction before getting the denominator.

   If "normalize" is "False", the expression is kept and if it is not
   a quotient, then this will just return 1.

Hence in your situation you could do

sage: t2.denominator(normalize=False)                                                                                                                                                          
x^2 - x
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Thx. ๐Ÿ™ˆ๐Ÿ™ˆ๐Ÿ™ˆ

Damm gravatar imageDamm ( 2021-04-26 08:37:24 +0100 )edit

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Asked: 2021-04-25 22:03:53 +0100

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Last updated: Apr 25