Translating GAP-output into sage for lattices

asked 2020-10-03 13:16:30 +0100

klaaa
691 ●4 ●17 ●41

updated 2020-10-03 13:19:50 +0100

Hi, I mainly use GAP for computations so my experience with Sage is very little. I wonder whether there is an easy method to translate a GAP statistic for posets into a sage statistic for lattices that can be used to enter in the database http://www.findstat.org/ . The following example illustrates the problem: The GAP output in this example is:

[ [ [ [ 1, 1, 1, 1, 1 ], [ 0, 1, 0, 0, 1 ], [ 0, 0, 1, 0, 1 ], [ 0, 0, 0, 1, 1 ], [ 0, 0, 0, 0, 1 ] ], 2 ],

[ [ [ 1, 1, 1, 1, 1 ], [ 0, 1, 0, 1, 1 ], [ 0, 0, 1, 1, 1 ], [ 0, 0, 0, 1, 1 ], [ 0, 0, 0, 0, 1 ] ], 2 ],

[ [ [ 1, 1, 1, 1, 1 ], [ 0, 1, 0, 0, 1 ], [ 0, 0, 1, 1, 1 ], [ 0, 0, 0, 1, 1 ], [ 0, 0, 0, 0, 1 ] ], 2 ],

[ [ [ 1, 1, 1, 1, 1 ], [ 0, 1, 1, 1, 1 ], [ 0, 0, 1, 1, 1 ], [ 0, 0, 0, 1, 1 ], [ 0, 0, 0, 0, 1 ] ], 1 ],

[ [ [ 1, 1, 1, 1, 1 ], [ 0, 1, 1, 1, 1 ], [ 0, 0, 1, 0, 1 ], [ 0, 0, 0, 1, 1 ], [ 0, 0, 0, 0, 1 ] ], 2 ] ]

This is a list with 5 entries where the first entry is for example [ [ [ 1, 1, 1, 1, 1 ], [ 0, 1, 0, 0, 1 ], [ 0, 0, 1, 0, 1 ], [ 0, 0, 0, 1, 1 ], [ 0, 0, 0, 0, 1 ] ], 2 ]. So this first entry is a list with two entries, the first is the matrix [ [ [ 1, 1, 1, 1, 1 ], [ 0, 1, 0, 0, 1 ], [ 0, 0, 1, 0, 1 ], [ 0, 0, 0, 1, 1 ], [ 0, 0, 0, 0, 1 ] ] that is the leq-matrix of a lattice, namely the diamond lattice (which in sage can be entered as ([(0,1),(0,2),(0,3),(1,4),(2,4),(3,4)],5) ) and the second entry is the number 2, which is the value of the statistic. So to every of the five entries in the big list, there corresponds a lattice with a number (statistic).

Now I try to obtain the same statistic in sage that can be entered in the findstat database and the text should look as follows:

([(0,1),(0,2),(0,3),(1,4),(2,4),(3,4)],5) => 2

([(0,2),(0,3),(2,4),(3,4),(4,1)],5) => 2

([(0,2),(0,3),(1,4),(2,4),(3,1)],5) => 2

([(0,4),(2,3),(3,1),(4,2)],5) => 1

([(0,3),(1,4),(2,4),(3,1),(3,2)],5) => 2

Is there an easy way to translate bigger lists such as the above GAP list automatically into the needed sage output to enter in the findstat database?

Thanks for any help!

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There are several steps you might be asking about:

convert a multiline string to sage objects: use sage_eval, see my answer
get that string from a file: use with open(filename, 'r') as f: s = f.read()
convert from a poset to a lattice or to hasse diagram edges: see @rburing's answer
string formatting to get the desired output form, see my answer

slelievre ( 2020-10-03 17:03:45 +0100 )edit

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answered 2020-10-03 16:58:21 +0100

slelievre
17704 ●22 ●160 ●350 http://carva.org/samue...

updated 2020-10-03 17:08:10 +0100

One possibility is to

input a mutli-line string from the GAP output
evaluate it as a list of "[list of lists, number]" lists
run a small loop to extract the data in the desired form

Here is how it would go.

The initial string:

s = """
[[[[1, 1, 1, 1, 1], [0, 1, 0, 0, 1], [0, 0, 1, 0, 1], [0, 0, 0, 1, 1], [0, 0, 0, 0, 1]], 2],
 [[[1, 1, 1, 1, 1], [0, 1, 0, 1, 1], [0, 0, 1, 1, 1], [0, 0, 0, 1, 1], [0, 0, 0, 0, 1]], 2],
 [[[1, 1, 1, 1, 1], [0, 1, 0, 0, 1], [0, 0, 1, 1, 1], [0, 0, 0, 1, 1], [0, 0, 0, 0, 1]], 2],
 [[[1, 1, 1, 1, 1], [0, 1, 1, 1, 1], [0, 0, 1, 1, 1], [0, 0, 0, 1, 1], [0, 0, 0, 0, 1]], 1],
 [[[1, 1, 1, 1, 1], [0, 1, 1, 1, 1], [0, 0, 1, 0, 1], [0, 0, 0, 1, 1], [0, 0, 0, 0, 1]], 2]]
"""

Turn it into a list:

sage: stats = sage_eval(s)
sage: stats
[[[[1, 1, 1, 1, 1],
   [0, 1, 0, 0, 1],
   [0, 0, 1, 0, 1],
   [0, 0, 0, 1, 1],
   [0, 0, 0, 0, 1]],
  2],
 [[[1, 1, 1, 1, 1],
   [0, 1, 0, 1, 1],
   [0, 0, 1, 1, 1],
   [0, 0, 0, 1, 1],
   [0, 0, 0, 0, 1]],
  2],
 [[[1, 1, 1, 1, 1],
   [0, 1, 0, 0, 1],
   [0, 0, 1, 1, 1],
   [0, 0, 0, 1, 1],
   [0, 0, 0, 0, 1]],
  2],
 [[[1, 1, 1, 1, 1],
   [0, 1, 1, 1, 1],
   [0, 0, 1, 1, 1],
   [0, 0, 0, 1, 1],
   [0, 0, 0, 0, 1]],
  1],
 [[[1, 1, 1, 1, 1],
   [0, 1, 1, 1, 1],
   [0, 0, 1, 0, 1],
   [0, 0, 0, 1, 1],
   [0, 0, 0, 0, 1]],
  2]]

Run the small loop to format as desired:

sage: for m, s in stats:
....:     a = matrix(m)
....:     i = a.parent().one()
....:     d = (a - i).dict()
....:     stat = list(d.keys()), a.ncols()
....:     print(f"{stat} => {s}")
....:
([(0, 1), (0, 2), (0, 3), (0, 4), (1, 4), (2, 4), (3, 4)], 5) => 2
([(0, 1), (0, 2), (0, 3), (0, 4), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)], 5) => 2
([(0, 1), (0, 2), (0, 3), (0, 4), (1, 4), (2, 3), (2, 4), (3, 4)], 5) => 2
([(0, 1), (0, 2), (0, 3), (0, 4), (1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)], 5) => 1
([(0, 1), (0, 2), (0, 3), (0, 4), (1, 2), (1, 3), (1, 4), (2, 4), (3, 4)], 5) => 2

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Thank you very much, this seems to work!

klaaa ( 2020-10-03 17:14:06 +0100 )edit

Be careful, after getting the matrix, I don't think I'm doing the right thing.

For the first matrix it works by luck, but for the other four it's not as expected in the question.

Check the code in @rburing's answer, and do the appropriate mix.

slelievre ( 2020-10-03 18:49:37 +0100 )edit

If you are working with GAP and Sage, you might also be interested in

running GAP computations from Sage using libgap.
Nicolas Thiéry's sage-gap semantic interface
running Sage computations from GAP using the Homalg GAP package

slelievre ( 2020-10-03 18:53:44 +0100 )edit

Thanks again. For findstat just the isomorphism type of the lattice is important and not the actual labeling (or using too many relations as you do in the example, since only the cover relations would be enough).

klaaa ( 2020-10-03 20:14:27 +0100 )edit

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answered 2020-10-03 16:53:59 +0100

rburing

10929 ●4 ●80 ●218 https://www.rburing.nl/

So essentially you want to turn a leq-matrix into a LatticePoset and get its Hasse diagram:

sage: M = Matrix([ [ 1, 1, 1, 1, 1 ], [ 0, 1, 1, 1, 1 ], [ 0, 0, 1, 1, 1 ], [ 0, 0, 0, 1, 1 ], [ 0, 0, 0, 0, 1 ] ])
sage: L = LatticePoset((range(M.nrows()), lambda i,j: M[i,j] == 1))
sage: H = L._hasse_diagram
sage: (H.edges(labels=False), len(H))
([(0, 1), (1, 2), (2, 3), (3, 4)], 5)

I don't understand why you write a different labeling of the vertices, but I hope this helps.

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Thanks... I got that part wrong!

slelievre ( 2020-10-03 17:04:57 +0100 )edit

The different labeling seems to be due to FindStat, but they don't explain anywhere how their canonical labeling works, as far as I can see.

rburing ( 2020-10-03 17:23:22 +0100 )edit

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