Is there a way to make log(e) print as 1? I know they're equal but I can't get sage to do that, and in complex expressions it's tedious to redo all the log(e)s.
f(x) = e^x*cos(x)
f_int(x) = integrate(f,x)
f_int(x)
result
(e^x*cos(x)*log(e) + e^x*sin(x))/(log(e)^2 + 1)
on Sage 9.2.beta13, WorksForMe(TM):
sage: integrate(f(x),x)
1/2*(cos(x) + sin(x))*e^x
Didn't you inadvertently redefine (= scratch) e ?
Building on @Emmanuel Charpentier's answer.
Below:
e is as when Sage startse is a symbolic variableeWith e as when Sage starts, no unsimplified log(e):
sage: log(e)
1
sage: f(x) = e^x*cos(x)
sage: f_int(x) = integrate(f, x)
sage: f_int(x)
1/2*(cos(x) + sin(x))*e^x
With e redefined as a symbolic variable, log(e) stays log(e):
sage: e = SR.var('e')
sage: log(e)
log(e)
sage: f(x) = e^x*cos(x)
sage: f_int(x) = integrate(f,x)
sage: f_int(x)
(e^x*cos(x)*log(e) + e^x*sin(x))/(log(e)^2 + 1)
To reset e to its default value, use either:
sage: reset('e')
or
sage: e = sage.symbolic.constants.e
or
sage: from sage.symbolic.constants import e
To figure out what import statement to use above, run this in a fresh Sage session:
sage: import_statements(e)
from sage.symbolic.constants import e
Asked: 2020-09-26 01:18:11 +0200
Seen: 332 times
Last updated: Sep 28 '20
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which Sagemath version ? I got :
1/2*(cos(x) + sin(x))*e^xwith 9.1moreover I got the same with
(e^x*cos(x)*log(e) + e^x*sin(x))/(log(e)^2 + 1).simplify()