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search for values in discrete range

asked 2020-09-22 19:29:57 -0600

brennan gravatar image

updated 2020-09-23 14:18:24 -0600

FrédéricC gravatar image

I am trying to search for solutions to a pair of equations but only using a few values. I know which values give the possible answers and I want to skip the computation time associated with checking every single value up within an interval. I am using the simple code:

for a in srange(0,200):
     for b in srange(1,a+1):
          if (a+b).is_square() and (a^2+b^2).is_square():
               print(a,b)

which gives me the solutions I want but it computes every integer solution from 0 to 200. If I know the answers, can I search for the range like

for a in range(9,21,28,36,40,84,112,133,156,160)

and then the same as above, and it will print:

28, 21

40, 9

112, 84

156,133

160,36

Any idea how to make that work? This is not homework or anything, just doing a bit of research and I'm a new. Thanks!!

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Comments

Then syntax is

for a in (9,21,28,36,40,84,112,133,156,160):
FrédéricC gravatar imageFrédéricC ( 2020-09-23 01:44:54 -0600 )edit

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answered 2020-09-23 01:44:39 -0600

Emmanuel Charpentier gravatar image

Just create the list of values to be searched, and loop on that:

A=(9,21,28,36,40,84,112,133,156,160)
for a in A:
    for b in srange(1,a+1):
        if (a+b).is_square() and (a^2+b^2).is_square():
            print(a,b)

gives

28 21
40 9
112 84
156 133
160 36
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Comments

Thank you so much!

brennan gravatar imagebrennan ( 2020-09-23 02:28:45 -0600 )edit

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Asked: 2020-09-22 19:29:57 -0600

Seen: 61 times

Last updated: Sep 23