# Assumption seems to break integrate(); is this a bug?

Consider the following Sage code (tested using Sage 8.6):

```
var('t')
var('a')
t.integrate(t, 0, a) # \int_{0}^{a} t dt
```

Output (as expected):

```
t
a
1/2*a^2
```

Next:

```
t.integrate(t, 0, 4*a - a^2) # 4*a - a^2 could be positive, negative, non-real(?)
```

Output (again, no problem):

```
1/2*a^4 - 4*a^3 + 8*a^2
```

Now suppose we give Sage a little more information. The following assumptions should guarantee that we're integrating over a real interval, and that the second (or "top") endpoint is strictly greater than the first ("bottom") endpoint. (Though as we have seen, Sage does not really need this information.)

```
assume(a, 'real')
assume(a > 1)
assume(a < 3) # now 0 < a < 4, so 4*a - a^2 > 0
t.integrate(t, 0, 4*a - a^2) # hangs, eventually produces RuntimeError
```

So, `.integrate()`

succeeds when nothing is known about the endpoint, but then fails when given more information.

**My Question: Is this desired/expected behavior, or would it be considered a bug?**

Personally, I found it surprising: I expected that, if a command worked with no assumptions, then it should still work after adding assumptions (consistent assumptions that only narrow the scope of the problem).

*What follows is purely my own speculation; feel free to ignore.*

I also get a similar kind of problem if I do the following:

```
forget()
var('t'); var('a');
assume(a, 'real')
assume(a > 1)
assume(a < 3)
bool(4*a - a^2 > 0) # hangs, RuntimeError
```

It seems to me that $1 < a < 3$ implies $0 < a < 4$, which implies that $-a^2 + 4a > 0$. (The graph of the quadratic is a downward-opening parabola, with roots at $0$ and $4$.) I am not surprised that Sage has trouble constructing this argument, so I am not surprised that the `bool()`

command hangs. But unfortunately this also seems to break `.integrate()`

, which was working otherwise.

So, I speculate that maybe the `.integrate()`

method, when faced with an integral whose endpoints are known to be real, first tries to figure out which endpoint is greater? But sometimes this process hangs, so the `.integrate()`

process never terminates?

In our case, I think Sage assumes by default that `a`

is complex-valued(?), and then it has no problem with the integral. So it seems like it should still work when `a`

is in the real interval $(1, 3)$, which after all is a subset of $\mathbb{C}$.

By the way, the following works just fine:

```
forget()
var('t'); var('a');
assume(4*a - a^2 > 0)
print(bool(4*a - a^2 > 0))
t.integrate(t, 0, 4*a - a^2)
```

Asked also at Math Stackexchange, but did not receive an answer there. Apologies if this kind of cross-posting is frowned upon.

I confirm the bug with Sage 9.2.beta5.

FWIW,

`t.integrate(t, 0, 4*a - a^2, algorithm='sympy')`

works.