why doesn't sage solve ln

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lolora
37 ●1 ●2 ●7

I have a simple equation to solve

solve(ln(x) -2 > 0,x)

The actual value should be $x > e^2$

but sagemath gives

[[log(x) - 2 > 0]]

How do I get actual value?

1 Answer

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Emmanuel Charpentier
7804 ●8 ●52 ●155

One possible solution:

sage: solve(log(x)-2>0,x, algorithm="sympy")
[x > e^2]

HTH,

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Last updated: Jul 05 '20