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why doesn't sage solve ln

asked 2020-07-05 03:32:28 +0200

lolora gravatar image

I have a simple equation to solve

solve(ln(x) -2 > 0,x)

The actual value should be $x > e^2$

but sagemath gives

[[log(x) - 2 > 0]]

How do I get actual value?

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answered 2020-07-05 08:38:37 +0200

Emmanuel Charpentier gravatar image

One possible solution:

sage: solve(log(x)-2>0,x, algorithm="sympy")
[x > e^2]


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Asked: 2020-07-05 03:32:28 +0200

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Last updated: Jul 05 '20