Let x1 ,x2,x3, v1,v2,v3 be the variable in a booleanpolynomialring. Let F = 1+ x1v1v2 + x2v1v2 + x1v3+ x2x3+ v1
Now what is the coefficient of v1v2? In this case it will be x1+x2. How can I find this using sagemath. I try to use F.coefficient(v1v2). But it not work. Plese help.
Homework ?
Just a hint, for now: if I understand you correctly, you're trying to use v1, v2, v3 as the indeterminates of a (boolean) polynomial whose coefficients are themselves boolean polynomials. Try to implement that...
i write this code:
from sage.crypto.boolean_function import BooleanFunction
B.<x1,x2,x3,v1,v2,v3> = BooleanPolynomialRing()
x = B.gens()
F = 1+ x1v1v2 + x2v1v2 + x1v3+ x2x3 + v1
F.coefficient(v1*v2)
but it shows :
Traceback (click to the left of this block for traceback)
...
AttributeError: 'sage.rings.polynomial.pbori.BooleanPolynomial' object
has no attribute 'coefficient'
Asked: 2019-10-28 05:48:35 +0100
Seen: 502 times
Last updated: Oct 29 '19
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