# Solving a differential equation - From SageManifold

I'm interested in solving a differential equation obtained from a calculation from `sagemanifold`

. I'll give a simple example, but the reason is that in general the equations **are not** as simple and one can introduce errors copying the equations.

I'd like to solve the equation given by the Ricci flat condition (for a certain affine connection).

```
reset()
M = Manifold(4, 'M', latex_name=r"\mathcal{M}")
U.<t,r,th,ph> = M.chart(r't r:(0,+oo) th:(0,pi):\theta ph:(0,2*pi):\phi')
nab = M.affine_connection('nabla', r'\nabla'); nab
k = var('k', latex_name=r'\kappa')
s = sqrt(1 - k * r**2)
f = function('f')(t)
g = function('g')(t)
h = function('h')(t)
nab[0,0,0] = f
nab[0,1,1] = g / (1 - k * r**2)
nab[0,2,2] = r**2 * g
nab[0,3,3] = r**2 * sin(th)**2 * g
nab[1,0,1] = h
nab[1,1,0] = h
nab[1,1,1] = k * r / (1 - k * r**2)
nab[1,2,2] = k * r**3 - r
nab[1,3,3] = (k * r **3 - r) * sin(th)**2
nab[2,0,2] = h
nab[2,1,2] = 1 / r
nab[2,2,0] = h
nab[2,2,1] = 1 / r
nab[2,3,3] = - cos(th) * sin(th)
nab[3,0,3] = h
nab[3,1,3] = 1 / r
nab[3,2,3] = cos(th) / sin(th)
nab[3,3,0] = h
nab[3,3,1] = 1 / r
nab[3,3,2] = cos(th) / sin(th)
nab.display()
Ric = M.tensor_field(0,2, 'R', latex_name=r'R')
Ric = nab.ricci()
print("Ricci tensor")
Ric.display_comp()
```

Now, the `Ric[0,0]`

component yield a simple equation, and can be solved by the command

```
desolve(diff(h,t) + h**2 - f*h, h, ivar=t, contrib_ode=True)
```

However, I'd like to be able of telling *Sage* the following

```
desolve( Ric[0,0], h, ivar=t, contrib_ode=True)
```

but it seems that there is an incompatibility of types here...

```
type(diff(h,t) + h**2 - f*h)
```

returns `<ππ’ππ'ππππ.ππ’ππππππ.ππ‘ππππππππ.π΄π‘ππππππππ'>`

, while

```
type(Ric[0,0])
```

returns `<πππππ'ππππ.πππππππππ.πππππβ―ππππ.π²πππππ΅πππππππππππβ―π πππβ―ππππππππ’.πππππππβ―πππππ'>`

**Question:**

What can I do to use the results from `sagemanifolds`

to solve the differential equation?