Hi,
I have a really simple problem. Assuming that I have this simple code
sage: rho = function("rho")(x)
sage: J = function("J")(x)
sage: expr = -J**2/rho**2*Derivative(rho, x) + 2*J/rho*Derivative(J, x)
Is there a way in sage to have this expression in a more compact expression. That is to say
Derivative(J**2/rho, x)
Thanks, Loic
WorksForMe(TM) :
sage: rho=function("rho")(x)
sage: J=function("J")(x)
sage: rho.diff(x)
diff(rho(x), x)
sage: (J**2/rho**2).diff(x).factor()
2*(rho(x)*diff(J(x), x) - J(x)*diff(rho(x), x))*J(x)/rho(x)^3
I. e. $$\frac{2 {\left(\rho\left(x\right) \frac{\partial}{\partial x}J\left(x\right) - J\left(x\right) \frac{\partial}{\partial x}\rho\left(x\right)\right)} J\left(x\right)}{\rho\left(x\right)^{3}}$$.
If you are dead set to use a "function call" syntax, it works, too :
sage: factor(diff(J**2/rho**2,x))
2*(rho(x)*diff(J(x), x) - J(x)*diff(rho(x), x))*J(x)/rho(x)^3
or even :
sage: factor(derivative(J**2/rho**2))
2*(rho(x)*diff(J(x), x) - J(x)*diff(rho(x), x))*J(x)/rho(x)^3
So where's your beef ? Oh, I see :
sage: Derivative(J**2/rho**2,x)
---------------------------------------------------------------------------
NameError Traceback (most recent call last)
<ipython-input-18-221717693903> in <module>()
----> 1 Derivative(J**Integer(2)/rho**Integer(2),x)
NameError: name 'Derivative' is not defined
So what ?
The asker is aware that, setting
sage: rho = function('rho')(x)
sage: J = function('J')(x)
both a and b below end up the same in Sage:
sage: a = -J**2/rho**2*diff(rho, x) + 2*J/rho*diff(J, x)
sage: b = (J**2/rho).diff(x)
sage: print('{}\n{}'.format(a, b))
2*J(x)*diff(J(x), x)/rho(x) - J(x)^2*diff(rho(x), x)/rho(x)^2
2*J(x)*diff(J(x), x)/rho(x) - J(x)^2*diff(rho(x), x)/rho(x)^2
The question is: is there a way, starting from a or b,
to transform the expression so that it prints as
diff(J(x)^2/rho(x), x)
which is a more compact representation.
While one can "hold" multiplication as follows, to prevent any simplification of an expression:
sage: rho = function('rho')(x)
sage: J = function('J')(x)
sage: a, b = J(x)/rho(x), rho(x)
sage: a * b
J(x)
sage: a.mul(b, hold=True)
(J(x)/rho(x))*rho(x)
the same is not true for differentiation:
sage: diff(J(x)^2/rho(x), x, hold=True)
Traceback (most recent call last)
...
TypeError: derivative() got an unexpected keyword argument 'hold'
The only workaround I can think of is this trick:
sage: f = function('(J^2/rho)')(x)
sage: diff(f, x)
diff((J^2/rho)(x), x)
sage: f = function('J(x)^2/rho')(x)
sage: diff(f, x)
diff(J(x)^2/rho(x), x)
which one might then try to combine with expression substitutions...
Asked: 2018-06-25 14:44:46 +0200
Seen: 372 times
Last updated: Jun 27 '18
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In principle, one could recognize this by taking the antiderivative of expr and recognizing the form you mention. However, the maxima backend that is used by default does not recognize this. Note that
diff(J**2/rho, x)returns the expression in the formexpr, soexpris considered the "simplified" form in that sense (it's certainly closer to a general standard form than the other). "compact for a human" is not always "best for computation".