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Factorization of $f \in \mathbb{Q}[X]$ in field extension $\mathbb{Q}(\alpha)$.

asked 2017-12-30 12:14:54 -0600

Rodrigo Raya gravatar image

updated 2017-12-30 13:04:30 -0600

I'm given an irreducible polynomial $f \in \mathbb{Q}[X]$ of degree 5 and I want to determine its Galois group without using the predefined functions of sage. The method I want to follow takes a root $\alpha_1$ of $f$ and studies the factorization of $f$ in the field extension $\mathbb{Q}(\alpha_1)$.

I believe this is possible with other software. How can I do it with sage?

Edit

Apparently, Abstract Algebra: An Interactive Approach, Second Edition but they use InitDomain function which is not recognized by my notebook.

Apparently the book gives a CD where an interface between sage and gap is done. So probably the solution requires using gap commands.

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It helps if you give an explicit example to get others started exploring your question.

slelievre gravatar imageslelievre ( 2017-12-30 17:16:49 -0600 )edit

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answered 2017-12-30 17:25:25 -0600

slelievre gravatar image

You could do something like the following.

$ sage -v
SageMath version 8.1, Release Date: 2017-12-07
$ sage -q
sage: P.<x> = QQ[]
sage: f = P([QQ.random_element() for _ in range(6)])
sage: f
x^4 - 2*x^3 - x^2 + x + 8
sage: f.roots()
[]
sage: f_roots = f.roots(QQbar, multiplicities=False)
sage: f_roots
[-0.9308781364905225? - 0.9859665944129413?*I,
 -0.9308781364905225? + 0.9859665944129413?*I,
 1.930878136490523? - 0.7891098514623471?*I,
 1.930878136490523? + 0.7891098514623471?*I]
sage: alpha = f_roots[0]
sage: K = QQ[alpha]
sage: K
Number Field in a with defining polynomial x^4 - 2*x^3 - x^2 + x + 8
sage: K['x'](f).factor()
(x - a) * (x^3 + (a - 2)*x^2 + (a^2 - 2*a - 1)*x + a^3 - 2*a^2 - a + 1)
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Asked: 2017-12-30 12:14:54 -0600

Seen: 103 times

Last updated: Dec 30 '17