# i doesn't belong to QQbar ? Why ?

I do not understand this :

```
sage: sqrt(1) in QQbar
True
sage: sqrt(-2) in QQbar
True
sage: sqrt(-1) in QQbar
False
```

Can someone explain ?

Note that, however :

```
sage: [t[0] in QQbar for t in (x^2+1).roots(ring=QQbar)]
[True, True]
```

Still the same bug on SageMath version 8.2, Release Date: 2018-05-05 . Nobody fix this? 0.0

1) This is not an answer...

2) see the mentioned ticket (as well as thetickets it refers to) to understand why there is not quick-and-easy fix for this one...

@Emmanuel Charpentier thanks for 1), my mistake. I decided to move back to linux, so my comment doesnt have sense anymore. Thanks for the feedback!