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Sage wrongly suggests there are only trivial solutions, why?

asked 7 years ago

Jo Be gravatar image

I have a system of two quadratic equations which I want to solve. WolframAlpha shows me whole families of solution, but sage says there are only trivial solutions. The equations are

dα2+αβ+αβ==0, dβ2+αβ+αβ==0, where d is constant and I want to solve for the complex numbers α,beta

I have the following minimal working example

var('a,b,q')
assume(a, 'complex')
assume(b, 'complex')
assume(q, 'real')

eq(x,y) = q*norm(x) + conjugate(x)*y + x*conjugate(y)

solution = solve([eq(a,b) == 0, eq(b,a) == 0], [a,b])
polySolution = solve([eq(a,b) == 0, eq(b,a) == 0], [a,b], to_poly_solve=True)

and the output then is

sage: solution
[[a == 0, b == 0]]
sage: polySolution
[[a == 0, b == 0]]

which is simply not correct.

Now, as I said, I have found solutions with WolframAlpha, but the next candidate I have to compute gives 18 equations in 5 complex variables, which I cannot possibly solve with WA. Sage, again, tells me that there are only trivial solutions, but because of this smaller example presented here, I believe that that is wrong.

Does anyone know how to force sage to give solutions?

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answered 7 years ago

nbruin gravatar image

The problem is that "conjugate" isn't C-linear, so the system of equations you are presenting isn't polynomial. Conjugation is R-linear, so if you write everything out in terms of real and imaginary parts, you're fine:

sage: var("x1,x2,y1,y2,d")
(x1, x2, y1, y2, d)
sage: alpha=x1+i*y1
sage: beta=x2+i*y2
sage: alpha_star=x1-i*y1
sage: beta_star=x2-i*y2
sage: Nalpha=alpha*alpha_star
sage: Nbeta=beta*beta_star
sage: eq1=d*Nalpha+alpha_star*beta+alpha*beta_star
sage: eq2=d*Nbeta+alpha_star*beta+alpha*beta_star

In order to solve these equations, you should split them in real and imaginary parts as well, but in this case the equations are already real:

sage: eq1.expand()
d*x1^2 + d*y1^2 + 2*x1*x2 + 2*y1*y2
sage: eq2.expand()
d*x2^2 + d*y2^2 + 2*x1*x2 + 2*y1*y2

Now you can just solve. To get better performance you might want to look into using polynomial rings instead.

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Asked: 7 years ago

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Last updated: Aug 15 '17