unable to convert floor(x) to an integer

asked 2017-06-18 00:19:18 +0100

515 ●9 ●20 ●38

Let's say, I want to define the following function:

sage: f(x)=mod(floor(x),5)

Then I get this error:

TypeError: unable to convert floor(x) to an integer

How can I solve this problem?

answered 2017-06-18 00:31:23 +0100

Sébastien
3271 ●7 ●42 ●88 http://www.slabbe.org/

updated 2017-06-18 00:34:23 +0100

By using f(x)= syntax, your are defining a Symbolic function of the symbolic variable x. Then floor(x) is a symbolic expression. And mod just don't eat a symbolic expression as first argument.

sage: a = floor(x)
sage: type(a)
<type 'sage.symbolic.expression.Expression'>
sage: mod(a, 5)   # raises type error

Use Python way of defining a function:

sage: def f(x): return mod(floor(x), 5)
sage: f(17.3)
2

See also this post or the section Some Common Issues with Functions in the Sage Guided tour.

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Comments

Thanks! How can I then get an output of the function instruction like in this example:

sage: g(x,y)=x-y
sage: g
(x, y) |--> x - y

Thrash ( 2017-06-18 00:41:05 +0100 )edit

For a Python function, unfortunately, you can not.

Sébastien ( 2017-06-18 02:42:23 +0100 )edit

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