Periodic function

edit

Well, frac is a misleading name in this case, since

sage: ( -1.5 ).frac()
-0.500000000000000

Or just plot:

plot(h,-3*pi,3*pi)

Thanks for the hint. I tried to improve my answer.

thanks, ndomes for your answer, bu the function should be even, yours is not :(. By the way are we obliged to rescale the function from [0, pi) to [0,1)? Is it not possible to solve this question directly (I mean without working on the interval [0,1))?

Sorry for my misunderstanding. I ignored the 'even' because the function you provided isn't even. The easiest way to build a periodic function is to start with a periodic function. The start interval depends on the function you use and therefore we may need axis transformations to get the desired result. One more suggestion:

f(x) = abs(arccos(cos(x))-pi)

I agree with you, that's why I initially started with this piece of code

v(x) = piecewise([([0, pi], -x + pi), ((pi, 2*pi), x - pi)])

where v is the function I want to duplicate all over the real line. But when I write

f(x) = v(T*RR(abs(x)/T).frac())

it raises an error, and it seems that the issue is coming from T*RR(abs(x)/T).frac().

Even though your answer is correct and defines the function I wanted, I still want to find a way to do the same with the piecewise function I defined earlier, can you help me with it?

... done in the spirit of the previous post.

Yeah that's the plot I wanted, but I don't understand the procedure. Can you explain it please?

I tried to use the already implemented functions, combined in a suitable way.

First of all, we need an even function, so it is natural to go through $x\to |x|$. This explains the inner most abs. Now we need to construct the shape of the function only for $x\ge 0$. (This already removes the problem in the first answer, i could have also easily fallen in the trap of the implemented frac function, which is not a periodic one, not the one from maths. People that did some computations with the Riemann $\zeta$--function may be highly confused.)

Then we need a periodic function, let us use frac on the positive real halfline. Notation $x\to{x}$. (The last notation is not the one element set, as my teacher joked each time he could...)

It has jumps at integer arguments, but the...

...but the slope is almost right, so let us make it continuous somehow. We consider then step by step: $$ x\to {x}\ , $$ $$ x\to {x}-\frac 12\ , $$ $$ x\to \left|\ {x}-\frac 12\ \right|\ , $$ now it is continuous, and it remains a small step, rescaling arguments, and values of the last function.

Note: I have no idea how to markdown + latex {x}. Abve i tried to display the functions: {x}, then {x}-1/2, finally | {x} - 1/2 |

OK, thanks for the explanation. I didn't get everything, but I'll take sometime to read and understand each step.