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Defining a periodic function.

asked 2013-09-14 23:57:16 -0500

lc gravatar image


I am a new sage user. I'd like to define simple periodic maps over \R which plot and integrate correctly (eg. a square signal (which of course is discontinuous but which I would still like to be able to plot in a way that makes it clear that the function is not multivalued at discontinuity points)). I tried different approaches none of which gave satisfactory results.

Any hint on how to do that nicely (or what would be the obstacles)?

Thank you

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John Palmieri gravatar imageJohn Palmieri ( 2013-09-17 18:39:55 -0500 )edit

3 answers

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answered 2013-09-18 07:37:39 -0500

nbruin gravatar image

The object you get out of Periodisation_int is not a symbolic function, but when you call it with x you get a symbolic expression anyway, so it doesn't really matter (and most symbolic machinery is for expressions anyway). If you really want a symbolic function you can do:

def per(f,a,b):
    x = SR.var('x')
    CSRx = CallableSymbolicExpressionRing( (x,))
    t = f((x-b)-(b-a)*floor((x-b)/(b-a)))
    h = CSRx(t)
    return h

where the whole bit with CSRx is to actually get a symbolic function (something you can call). I'm not so sure that integrate knows what to do with this symbolic function, though.

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answered 2013-09-15 00:55:07 -0500

tmonteil gravatar image

updated 2013-09-15 01:00:50 -0500

You should tell us about your different approaches, and what was wrong with them. I am not sure whether you ask about defining a function or plotting it. Here would be my direct lazy approach, without more informations about your needs. To define a periodic function, use the .frac() method of real numbers. In your case:

sage: f = lambda x: 1 if RR(x).frac() < 1/2 else 0
sage: plot(f, 0, 4)

If you do not like the vertical line at the discontinuities, you can look at the options of the plot() function:

sage: plot?

In your case, you can try:

sage: plot(f, 0, 4, plot_points='1000', linestyle='', marker='.')

For the integral, since the finction is defined point by points (not a symbolic function), you can do a numerical integration:

sage: numerical_integral(f, 0, 4)
(2.0, 2.2315482794965646e-14)
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answered 2013-09-16 03:00:37 -0500

lc gravatar image

Thank-you for the quick answer.

frac() gives a function which is periodic on positive reals. I just adapted your solution to get it periodic on \RR.

f = lambda x: 1 if (x - RR(x).floor()) < 1/2 else 0

I would have liked to be able to define a symbolic function though. Is it doable?

I was also trying to get a function whose plot is correct (without asking it to be pointwise) as it is the case for Piecewise().

Below are some of the things (not chronologically ordred though) I had tried (just for completness as I guess they are just full of beginer's classical mistakes).


which does not evaluate


returns ValueError: cannot convert float NaN to integer.


returns ValueError: Value not defined outside of domain.


also returns ValueError: Value not defined outside of domain.

I also tried to redefine unit_step:

def echelon_unite(x):
    if x<0:
    return hres

problem integral(echelon_unite(x),x,-10,3) returns 13

numerical integral returns a coherent result.

Other tentative with incoherent result (still with integrate and not numerical_integral)

  def Periodisation_int(f,a,b):
        x = var('x')
        h0(x) = (x-b)-(b-a)*floor((x-b)/(b-a))
        hres = compose(f,h0)
        return hres

sage: g=Periodisation_int(sin,0,1)
sage: integrate(g(x),x,0,2)
-cos(1) + 2
sage: integrate(g(x),x,0,1)
-cos(1) + 1
sage: integrate(g(x),x,1,2)
-1/2*cos(1) + 1

My guess is I was using integrate on inappropriate objects. I would still like to know how to define corresponding symbolic function (if it is possible).

Thanks again,

best regards.

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Asked: 2013-09-14 23:57:16 -0500

Seen: 798 times

Last updated: Sep 18 '13