Loading [MathJax]/jax/output/HTML-CSS/jax.js
Ask Your Question
0

Computation of reduced Grobner basis

asked 8 years ago

Nilesh gravatar image

updated 0 years ago

FrédéricC gravatar image

Currently I am reading one research paper http://www.ijpam.eu/contents/2010-62-... on page 486 equation 9 and 10 are describing an ideal, whereas on page 487 , Grobner basis has been calculated w.r.t ideal associated with ternary Goaly code.I understood the proof on page 486, but unable to compute the Grobner basis by using sage.

Preview: (hide)

Comments

@Nilesh -- Please describe what you have tried so far. Have you been able to define the ideal?

slelievre gravatar imageslelievre ( 8 years ago )

No, I am not getting, how to define this ideal? I have created following generator matrix of a linear code i.e.ternary Golay code using sage G2=matrix(FiniteField(3),[[1,0,0,0,0,0,1,1,1,1,1], [0,1,0,0,0,0,0,1,2,2,1], [0,0,1,0,0,0,1,0,1,2,2], [0,0,0,1,0,0,2,1,0,1,2], [0,0,0,0,1,0,2,2,1,0,1], [0,0,0,0,0,1,1,2,2,1,0]]) print(G2) C = LinearCode(G2); C C.length()

But then not able to construct the ideal viz: I=<x^c-x^c' c-c'="" belongs="" to="" c="">+<xi^p-1 1&lt;="i&lt;=n">, I think,once ideal is constructed, then next thing will be easy.

Nilesh gravatar imageNilesh ( 8 years ago )

1 Answer

Sort by » oldest newest most voted
1

answered 8 years ago

dan_fulea gravatar image

If i've got the right message of the cited paper, than the following sage code computes the toric ideal I of the (Z-lift of the) parity check matrix for the linear code C of G=G2 posted above, also associates the ideal J generated by the X3j1, Xj being a running variable through the ones of the polynomial ring of I, then takes the sum K = I + J . Its generator list is the sum of the two generator lists for I and J.

This K is the ideal IC from (9) and (10) of loc. cit.

We finally compute the Groebner basis of K as in the Example of loc. cit., page 487.

(In order to get the right basis, it is important to have the lex order on the ring R, where I,J,K live in. The default order leads to a mess. So the first line is the important one, then we pass this polynomial ring to the ToricIdeal constructor.)

R.<X01, X02, X03, X04, X05, X06, X07, X08, X09, X10, X11> \
    = PolynomialRing( QQ, order='lex' )    # sine lex, nulla salus 

G = matrix( GF(3),
            [ [1,0,0,0,0,0, 1,1,1,1,1] ,
              [0,1,0,0,0,0, 0,1,2,2,1] ,
              [0,0,1,0,0,0, 1,0,1,2,2] ,
              [0,0,0,1,0,0, 2,1,0,1,2] ,
              [0,0,0,0,1,0, 2,2,1,0,1] ,
              [0,0,0,0,0,1, 1,2,2,1,0] ] )
# This is [ I | M ] as in loc. cit., Example, page 487.
print G
C = LinearCode( G )
print C

H = C.parity_check_matrix()
# we do not print H

I = ToricIdeal( H, polynomial_ring = R )
J = ideal( z^3-1 for z in I.parent().ring().gens() )
K = I + J

print "\nI is generated by:"
for pol in I.gens():    print "    %s" % pol

print "\nJ is generated by:"
for pol in J.gens():    print "    %s" % pol

print "\nK is generated by:"
for pol in K.gens():    print "    %s" % pol

print "\nK has the Groebner basis:"
for pol in K.groebner_basis():    print "    %s" % pol

This delivers:

[1 0 0 0 0 0 1 1 1 1 1]
[0 1 0 0 0 0 0 1 2 2 1]
[0 0 1 0 0 0 1 0 1 2 2]
[0 0 0 1 0 0 2 1 0 1 2]
[0 0 0 0 1 0 2 2 1 0 1]
[0 0 0 0 0 1 1 2 2 1 0]
Linear code of length 11, dimension 6 over Finite Field of size 3

I is generated by:
    -X01*X02*X03^2*X04^2*X05 + X11
    -X01*X02*X03*X05^2 + X10
    -X01*X03^2*X04*X05^2 + X09
    -X01*X02^2*X03*X04^2 + X08
    -X01*X02^2*X04*X05 + X07
    -X02^2*X03^2*X04^2*X05^2 + X06

J is generated by:
    X01^3 - 1
    X02^3 - 1
    X03^3 - 1
    X04^3 - 1
    X05^3 - 1
    X06^3 - 1
    X07^3 - 1
    X08^3 - 1
    X09^3 - 1
    X10^3 - 1
    X11^3 - 1

K is generated by:
    -X01*X02*X03^2*X04^2*X05 + X11
    -X01*X02*X03*X05^2 + X10
    -X01*X03^2*X04*X05^2 + X09
    -X01*X02^2*X03*X04^2 + X08
    -X01*X02^2*X04*X05 + X07
    -X02^2*X03^2*X04^2*X05^2 + X06
    X01^3 - 1
    X02^3 - 1
    X03^3 - 1
    X04^3 - 1
    X05^3 - 1
    X06^3 - 1
    X07^3 - 1
    X08^3 - 1
    X09^3 - 1
    X10^3 - 1
    X11^3 - 1

K has the Groebner basis:
    X01 - X07^2*X08^2*X09^2*X10^2*X11^2
    X02 - X08^2*X09*X10*X11^2
    X03 - X07^2*X09^2*X10*X11
    X04 - X07*X08^2*X10^2*X11
    X05 - X07*X08*X09^2*X11^2
    X06 - X07^2*X08*X09*X10^2
    X07^3 - 1
    X08^3 - 1
    X09^3 - 1
    X10^3 - 1
    X11^3 - 1

And matches.

Preview: (hide)
link

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

1 follower

Stats

Asked: 8 years ago

Seen: 636 times

Last updated: Mar 29 '17