nth root of huge number

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If you are looking for a numerical approximation, there are several routes open to you. Here are two.

• You can approximate after taking it with e.g. a.n(digits=100), like here
• You can use a decimal point like 383. instead of 383 and then do the root

More advanced options include setting a "real field" with a certain accuracy like R=RealField(1000) and using that ...

If you are wondering whether this number is a perfect power, you can check that it is divisible by 7 but not by 7^2.

sage: a = 383359376317228026832765614031101780857214373741934853796883469684751393959423303934031779306976105234618634914722122231966050161090557311139688754390702005669975825514220776140658553598335180339644221202109745240693646681489614040361698983885974381266138822986136754230956173498395067036601233601299698337833849969027885834924082799260330843401454066113756946449729494314541583444719025620597701816509274146453
sage: a % 7
0
sage: a % 7^2
28