sqrt stands for "square root", so 3*sqrt(3) means $3\sqrt{3}$.
Now, if you want a numerical representation of your number, you can use the .n() method:
sage: a = 3*sqrt(3)
sage: a.n()
5.19615242270663
I want to know that how can sqrt(27) can be 3*sqrt(3). I know that I can get the decimal value by using .n() or .numerical_approx() but I want to know that what does that statement really mean? and how it is useful for a user?, I mean it should directly shown the value given by .numerical_approx() function.
I am very thankful that you replied to my question. Actually I am starting contributing to sage so it is necessary to understand each and every output.
It would be great if you help me a bit more.
@tmonteil, this seems weird. Why should Meth:sqrt return a simplified expression instead of the direct numerical value in some cases and not others? For instance, sqrt(6.1) gives 2. something directly, while I have to do n(sqrt(27)) to get 5. I get that this can be simplified and so it is, but why should that be its native behaviour instead of the decimal value? Also, is this a native Sage method or does it belong to some other package?
Asked: 2016-10-02 15:53:35 +0100
Seen: 3,311 times
Last updated: Oct 03 '16
Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.
