Consider a finite set l of points in R^4. I define a polyotpe with P= Polyhedron(l). I consider the set of faces of dimension 2 with P.faces(2).
My question is to find the set of faces of dimension 2 which contains one vertex. What is the command ? Best regards,
You can do a Python list extension as follows:
sage: C = polytopes.hypercube(4) ; C
A 4-dimensional polyhedron in ZZ^4 defined as the convex hull of 16 vertices
sage: v = C.vertices()[0] ; v
A vertex at (-1, -1, -1, -1)
sage: [f for f in C.faces(2) if v in f.vertices()]
[<0,1,2,3>, <0,1,4,5>, <0,2,4,6>, <0,1,8,9>, <0,2,8,10>, <0,4,8,12>]Asked: 8 years ago
Seen: 814 times
Last updated: Sep 12 '16
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