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More digits from octave

asked 2016-07-22 05:37:53 -0500

Marco Caliari gravatar image

Hi, how can I get all the 15/16 digits from a command like pi = octave('pi')?

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answered 2016-07-29 07:04:51 -0500

Marco Caliari gravatar image

Hi, I found myself a solution, for instance:

a=Matrix(RR,octave('sprintf("%.16e ",rand(1,4))'))
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answered 2016-07-22 13:12:46 -0500

nbruin gravatar image

As far as I know, the "octave" command really just gets you an interface that allows you to pass strings as "typed in to octave" and get you back strings as printed by octave. So:

  octave:1> 0.123456789
  ans =  0.12346

suggests octave is naturally stingy with printing digits. In order to get more digits back via the octave interface, you should do whatever you do to normally coerce octave to print more digits. Perhaps https://www.gnu.org/software/octave/d... helps.

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answered 2016-07-22 06:45:42 -0500

Starting Octave just to get a numerical value of pi is unnecessarily slow.

If you need a floating-point approximation to pi, I would suggest:

sage: pi = RDF.pi()
sage: pi
3.141592653589793

But maybe you have other reasons to use Octave?

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Sorry, try this instead a=octave('0.123456789'). I chose pi just to be short. I get a=0.123457, lost two digits.

Marco Caliari gravatar imageMarco Caliari ( 2016-07-22 07:56:39 -0500 )edit

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Asked: 2016-07-22 05:37:53 -0500

Seen: 119 times

Last updated: Jul 29 '16