I would like to check if one cone contains another cone, where the cones are convex rational polyhedral cones. I don't want to compute the intersection of two cones, because when done many times, that becomes prohibitively slow. Checking containment should be much faster. Is this possible in Sage? Thanks!
Assuming that your cones only contains the vertex 0, you can use containment as follows
sage: def polyhedron_contains(P, Q):
....: return all(P.contains(v) for v in Q.rays())
sage: P1 = Polyhedron(rays = [(1,0,0), (0,1,0), (0,0,1)])
sage: P2 = Polyhedron(rays = [(1,2,1), (1,0,0), (1,1,1), (1,1,2)])
sage: polyhedron_contains(P1,P2)
True
Asked: 2015-12-28 20:59:45 +0100
Seen: 4,620 times
Last updated: Dec 28 '15
Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.