# How can i counter frequent array in numpy?

import numpy as np X=np.array[[1,2], [3,4], [1,2], [4,1]] "i want to counter repetitive [1,2]"

How can i counter frequent array in numpy?

import numpy as np X=np.array[[1,2], [3,4], [1,2], [4,1]] "i want to counter repetitive [1,2]"

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It is somehow a duplicate of this question, you can change the bi-dimensional numpy array `X`

into a list of lists as follows:

```
sage: Y = [list(x) for x in X]
sage: Y
[[1, 2], [3, 4], [1, 2], [4, 1]]
```

Asked: **
2015-12-12 09:25:28 -0500
**

Seen: **138 times**

Last updated: **Dec 13 '15**

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