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LU decomposition for a matrix

asked 9 years ago

rafarob32 gravatar image

updated 2 years ago

tmonteil gravatar image

There is an inconsistency in the use of the LU decomposition of a matrix. If matrix A is declared in the RDF ring then P, L, U = A.LU () provides PA = LU but if A is declared in the RR ring (or QQ, ZZ,...) then A = PLU. Therefore in a case P is P.transpose () on the other.

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answered 9 years ago

tmonteil gravatar image

updated 9 years ago

While this is correctly documented (hence not a bug), i agree that there is some inconsistency here. Thanks for reporting, it is now trac ticket 18365.

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Asked: 9 years ago

Seen: 2,970 times

Last updated: May 05 '15