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# breaking out of while, for loops. Anonymous

Hello.

Actually, my problem is to get all new representatives.

But I think it is only an algorithmic problem to me.

My consideration is following:

1. Let A be a group and Rep=[A]. And i=0

2. Make i=i+1 and the list L of all subgroups with index 2^i.

3. Make empty list New.

4. For B in L, if B is not conjugate to any group in Rep then add to Rep and add to New else do nothing.

5. If New is empty then return Rep else make New empty list and go to STEP 2.

How can I do this in SAGE....

I cannot give a simple example. :(

In my problem,

1. A=[1,x,x^2], Rep=[A], i=0 (A is a generator of the rank 3 Z-module in Z[x])

2. i=i+1, L : the list of all submodule of A with index 2^i.

3. New=[]

4. For B in L, [ For C in Rep, t=False, if B~C then t=true. ] If t=False then Rep=Rep+[B] and New=New+[B]

5. If len(New)==0 then return Rep else New=[] and go to STEP 2.

If you have some question I WILL answer as soon as possible. :)

Thanks.

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## 1 answer

Sort by » oldest newest most voted Here are two example functions illustrating breaking out of while and for loops:

def f():
index = 0
while True:
print index
index += 1
if index >= 4:
break

def g():
for i in range(10):
if i >= 5:
continue
print i

more

## Comments

Thanks! It's useful to me. Using that algorithm, I solved my problem, roughly~. :)

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Asked: 2014-11-22 04:04:18 -0500

Seen: 2,779 times

Last updated: Nov 22 '14