Ask Your Question
0

Divisibility

asked 2014-10-18 17:32:22 +0100

anonymous user

Anonymous

updated 2014-10-18 17:46:29 +0100

vdelecroix gravatar image

To find numbers of the form 7aaa that are multiples of 7, I use:

sage:print [a for a in [0..9] if (7000+111*a)%7==0]
[0, 7]

I do not know how to write for 7|7abc.

Thanks.

edit retag flag offensive close merge delete

Comments

I reedit your question. Please double check that it is all right. It was not very clear.

vdelecroix gravatar imagevdelecroix ( 2014-10-18 17:45:49 +0100 )edit

Thank you for edit.

masac gravatar imagemasac ( 2014-10-18 17:48:27 +0100 )edit

2 Answers

Sort by ยป oldest newest most voted
0

answered 2014-10-18 17:51:02 +0100

vdelecroix gravatar image

Hello,

There are various solutions. To generate the list of numbers of the form 7abc, you can use one of:

sage: numbers0 = range(7000,8000)
sage: numbers1 = [7000 + x for x in range(1000)]
sage: numbers2 = [7000 + a*100 + b*10 + c for a in range(10) for b in range(10) for c in range(10)]

Then you can check divisibility the very same way you did. But note that there is a faster way since x is a multiple of 7 if and only if x+7 is a multiple of 7. So once you find one, you only need to go 7 by 7.

Is that ok ?

Vincent

edit flag offensive delete link more
0

answered 2014-10-18 18:09:42 +0100

masac gravatar image

updated 2014-10-18 18:17:50 +0100

I tried:

sage: a=range(7000,8000)
sage: print[a if a%7==0]
  File "<ipython-input-30-590163f2a51e>", line 1
print[a if a%Integer(7)==Integer(0)]
                                   ^
 SyntaxError: invalid syntax

I find a solution:

print [a for a in [7000..7999] if a%7==0]

Thank you for support.

edit flag offensive delete link more

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

1 follower

Stats

Asked: 2014-10-18 17:32:22 +0100

Seen: 2,447 times

Last updated: Oct 18 '14