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TypeError: 'sage.rings.integer.Integer' object is not callable

asked 2014-04-28 05:48:35 -0600

Caterpillar gravatar image

I tried to enter into notebook:



And I obtained error

Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "", line 10, in <module> exec compile(u'open("","w").write("# -- coding: utf-8 --\n" + _support_.preparse_worksheet_cell(base64.b64decode("KC0oKGEtMSleMiktKCgtYS04KSgyKGEtMSkpKSkvKChhLTEpXjQp"),globals())+"\n"); execfile(os.path.abspath("")) File "", line 1, in <module> File "/tmp/tmpF91cWI/", line 3, in <module> exec compile(u'(-((a-_sage_const_1 )_sage_const_2 )-((-a-_sage_const_8 )(_sage_const_2 (a-_sage_const_1 ))))/((a-_sage_const_1 )_sage_const_4 ) File "", line 1, in <module> TypeError: 'sage.rings.integer.Integer' object is not callable

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answered 2014-04-28 06:53:38 -0600

kcrisman gravatar image

Yup! That's because 2(a-1) does not make sense in Sage. If you had defined f(x)=2+x or something, f(a-1) would be legal.

However, since you were probably trying to do implicit multiplication (as opposed to explicit 2*(a-1)), there is another option. You can turn on implicit multiplication if you wish. But beware - it is fragile! Good luck.

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Asked: 2014-04-28 05:48:35 -0600

Seen: 5,285 times

Last updated: Apr 28 '14