Ask Your Question
1

Quotient of free algebra on 2 generators (x, y) over rational field by a non-homogenous ideal

asked 2013-10-09 11:50:37 +0200

this post is marked as community wiki

This post is a wiki. Anyone with karma >750 is welcome to improve it.

Hi all,

Here I asked a question in sage but there is an error which I can not solve it:

F.<x,y>=FreeAlgebra(QQ)
I=F*[x*y*x*y-y*x, y*x*y*x-x*y]*F
G.<a,b>=F.quo(I)
G

TypeError: quotient() takes exactly 4 arguments (3 given)


Please help me to find the forth argument should I put.

Actually I want to construct a quotient of infinite dimensional non-commutative free algebra F by a non-homogenous ideal.

Thanks

edit retag flag offensive close merge delete

1 Answer

Sort by ยป oldest newest most voted
1

answered 2013-10-09 21:19:24 +0200

this post is marked as community wiki

This post is a wiki. Anyone with karma >750 is welcome to improve it.

It doesn't look like general quotients of free algebras are implemented. See Sage's reference manual for one way to do this: implement a reduce method for your ideal, as in the PowerIdeal class defined in the example. See also the documentation for QuotientRing, although the examples there don't look as helpful.

edit flag offensive delete link more

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

Stats

Asked: 2013-10-09 11:50:37 +0200

Seen: 190 times

Last updated: Oct 09 '13